Python program to check given character is vowel or consonant

In this tutorial we are going to learn writing python program to check given character is a vowel ( a, e, i, o, u) or any other alphabet other than vowels(consonant) .

Problem statement

For any input character, we have to check whether a character is a vowel or consonant.

For example:

Case 1: If a user is given input a or A

              The output should be “Vowel”

              As we know that A is a vowel

Case2: If the user is given b or B

             The output should be “consonant”

             As we know that B is consonant

Our logic to check given character is vowel or consonant

• Our program will take any character as an input from the user
• Then checks if the character taken belongs to vowels or consonants, we achieve this using if-else conditional statements.

Python code to check given character is vowel or consonant

ch = input("Enter a character to check if it's a vowel or consonant: ")

# Check if input is a single alphabet character
if len(ch) == 1 and ch.isalpha():
    if ch.lower() in ('a', 'e', 'i', 'o', 'u'):
        print("Given character", ch, "is a vowel")
    else:
        print("Given character", ch, "is a consonant")
else:
    print("Please enter a single alphabet character only.")

Output 1:

Enter a character to check if it's a vowel or consonant: o
Given character o is a vowel

Explanation:

As we can see for the character ‘o’ output generated is “Vowel”, which is obvious as o is a vowel and satisfying the ‘if ’ statement  

Output 2:

Enter a character to check if it's a vowel or consonant: t
Given character t is a consonant

Explanation:

Similarly, for the character ‘t’ output generated is “consonant”, as ‘t’ is not a vowel and does not satisfy the ‘if ’ statement