Practice Questions
Concept Explanation
Growth (or appreciation) increases a quantity each year at a fixed rate, using the compound interest formula with an increase.
Key Formula
Value after T years = P(1 + R/100)^T
Example
Population 1,00,000 grows at 10% p.a. After 2 years: 100000 × 1.1^2 = 1,21,000.
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Q1 Easy
Population 1,00,000 grows at 10% p.a. After 2 years it is:
ExplanationPopulation = 100000 × (1.1)^2 = 1,21,000. -
Q2 Easy
Rs. 50,000 grows at 20% p.a. Value after 2 years is:
ExplanationValue = 50000 × (1.2)^2 = Rs. 72,000. -
Q3 Medium
Town population 80,000 grows at 5% p.a. After 2 years:
ExplanationPopulation = 80000 × (1.05)^2 = 88,200. -
Q4 Medium
Rs. 1,00,000 appreciates at 8% p.a. Value after 2 years is:
ExplanationValue = 100000 × (1.08)^2 = Rs. 1,16,640. -
Q5 Hard
Population 50,000 grows at 10% for 3 years. Population becomes:
ExplanationPopulation = 50000 × (1.1)^3 = 66,550. -
Q6 Easy
Rs. 25,000 grows at 20% for 2 years. Value is:
ExplanationValue = 25000 × (1.2)^2 = Rs. 36,000. -
Q7 Hard
Population 1,20,000 grows at 5% for 3 years. Population is:
ExplanationPopulation = 120000 × (1.05)^3 = 1,38,915.
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Q8 Easy
Rs. 40,000 appreciates at 10% for 2 years. Value is:
ExplanationValue = 40000 × (1.1)^2 = Rs. 48,400. -
Q9 Medium
Population 60,000 grows at 20% for 2 years. Population is:
ExplanationPopulation = 60000 × (1.2)^2 = 86,400. -
Q10 Medium
Rs. 1,50,000 grows at 5% for 2 years. Value is:
ExplanationValue = 150000 × (1.05)^2 = Rs. 165,375. -
Q11 Easy
Population 2,00,000 grows at 10% for 1 year. Population is:
ExplanationPopulation = 200000 × 1.1 = 2,20,000. -
Q12 Medium
Rs. 80,000 appreciates at 8% for 2 years. Value is:
ExplanationValue = 80000 × (1.08)^2 = Rs. 93,312. -
Q13 Hard
Population 1,00,000 grows at 4% for 3 years. Population is:
ExplanationPopulation = 100000 × (1.04)^3 = 1,12,486.40, approximately 1,12,486. -
Q14 Medium
Rs. 60,000 grows at 10% for 3 years. Value is:
ExplanationValue = 60000 × (1.1)^3 = Rs. 79,860.
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DS1 Easy
What is the population after growth?
Statement IInitial population is 1,00,000 growing at 10% for 2 years.
Statement IIGrowth rate is 10% p.a.
ExplanationStatement I alone gives population = 1,21,000. -
DS2 Medium
What is the value after appreciation?
Statement IInitial value is Rs. 50,000.
Statement IIGrowth rate is 20% per annum for 2 years.
ExplanationNeed initial value, rate and time together. Value = Rs. 72,000.
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DS3 Hard
What is the population after 3 years?
Statement IInitial population is 50,000.
Statement IIGrowth rate is 10% per annum.
ExplanationTogether: population = 66,550. -
DS4 Medium
Is the value greater than Rs. 1,00,000 after 2 years?
Statement IRs. 80,000 appreciates at 8% for 2 years.
Statement IIRate is 8%.
ExplanationStatement I: value = Rs. 93,312, so the answer is no — statement I alone is sufficient.